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Q. An electron in $H$ -atom in its ground state absorbs 1.5 times as much as energy as the minimum required for its escape from the atom
$H ( g ) \longrightarrow H ^{+}( g )+ e ^{-} ; \,\,\,\Delta H =13.6 eV atom ^{-1}$
Thus, kinetic energy given to the emitted electron is

Structure of Atom

Solution:

$\underset{**}{E _{1}}=$ Energy of $H$ -atom in the ground state $=13.6 \,eV$

Energy absorbed $=(13.6 \times 1.5)=20.4\, eV$

$E _{2}=$ Energy of the excited state

$=13.6+20.4=34.0\, eV$

$\Delta E = KE =\left( E _{2}- E _{1}\right)$

$=34.0-13.6=20.4 \,eV$