An electron in a circular orbit of radius .05 nm performs 1016 revolutions per second. The magnetic moment due to this rotation of electron is (in Am2)

Question

An electron in a circular orbit of radius .05 nm performs 1016 revolutions per second. The magnetic moment due to this rotation of electron is (in Am2) (A) 2.16 × 10-23 (B) 3.21 × 10-22 (C) 3.21 × 10-24 (D) 1.26 × 10-23

Tardigrade Admin · Accepted Answer

Given, r=0.05 nm =0.05 × 10-9 m (∵ 1 nm =10-9 m ) n=1016 revolutions e=1.6 × 10-19 C We know that The magnetic moment M=A i M=π r2 × n e M=3.14 ×(0.05 × 10-9)2 × 1016 × 1.6 × 10-19 M=0.1256 × 10-18 × 1016 × 10-19 or M=1.26 × 10-23 Am 2

Q. An electron in a circular orbit of radius . $05$ nm performs $1 0^{16}$ revolutions per second. The magnetic moment due to this rotation of electron is (in $A m^{2}$ )

$2.16 \times 1 0^{- 23}$

$3.21 \times 1 0^{- 22}$

$3.21 \times 1 0^{- 24}$

$1.26 \times 1 0^{- 23}$

Q. An electron in a circular orbit of radius .05 nm performs 1016 revolutions per second. The magnetic moment due to this rotation of electron is (in Am2)

2.16×10−23

3.21×10−22

3.21×10−24

1.26×10−23

Given, r=0.05nm=0.05×10−9m (∵1nm=10−9m) n=1016 revolutions e=1.6×10−19C We know that The magnetic moment M=Ai M=πr2×ne M=3.14×(0.05×10−9)2×1016×1.6×10−19 M=0.1256×10−18×1016×10−19 or M=1.26×10−23Am2

Q. An electron in a circular orbit of radius . $05$ nm performs $1 0^{16}$ revolutions per second. The magnetic moment due to this rotation of electron is (in $A m^{2}$ )

$2.16 \times 1 0^{- 23}$

$3.21 \times 1 0^{- 22}$

$3.21 \times 1 0^{- 24}$

$1.26 \times 1 0^{- 23}$