An electromagnetic wave going through vacuum is described by E=E0 sin (k x-ω t) . Which of the following is independent of wavelength?

Question

An electromagnetic wave going through vacuum is described by E=E0 sin (k x-ω t) . Which of the following is independent of wavelength? (A) k (B) ω (C) k / ω (D) k ω

Tardigrade Admin · Accepted Answer

The angular wave number k=(2 π/λ) ; where λ is the wavelength. The angular frequency is ω=2 π v. The ratio (k/ω)=(2 π / λ/2 π v) =(1/v π)=(1/c)= constant

Q. An electromagnetic wave going through vacuum is described by $E = E_{0} sin (k x - ω t) .$ Which of the following is independent of wavelength?

$k$

$ω$

$k / ω$

$kω$

The angular wave number $k = \frac{2 π}{λ};$ where $λ$ is the wavelength.
The angular frequency is $ω = 2 π v$ .
The ratio $\frac{k}{ω} = \frac{2 π / λ}{2 π v}$
$= \frac{1}{v π} = \frac{1}{c} =$ constant

Q. An electromagnetic wave going through vacuum is described by E=E0​sin(kx−ωt). Which of the following is independent of wavelength?

k

ω

k/ω

kω

The angular wave number k=λ2π​; where λ is the wavelength. The angular frequency is ω=2πv. The ratio ωk​=2πv2π/λ​ =vπ1​=c1​= constant

Q. An electromagnetic wave going through vacuum is described by $E = E_{0} sin (k x - ω t) .$ Which of the following is independent of wavelength?

$k$

$ω$

$k / ω$

$kω$

The angular wave number $k = \frac{2 π}{λ};$ where $λ$ is the wavelength.
The angular frequency is $ω = 2 π v$ .
The ratio $\frac{k}{ω} = \frac{2 π / λ}{2 π v}$
$= \frac{1}{v π} = \frac{1}{c} =$ constant