Q.
An electric motor is used to fill an overhead tank of capacity 10m3 kept at a height of 20m above the ground. If the pump takes 6 minutes to fill the tank by consuming 20kW power the efficiency of the pump should be (g=10m/s2)
work done in raising water =mgh. w=( volume × density )×gh(ρ=1000kg/m3) w=10×1000×10×20=2×106J
Power = time work =6×602×106=0.0055×106=5.5×103 P=5.5KW .∴ Efficiency =205.5×100=27.5%