An electric dipole of moment vecp is placed normal to the lines of force of electric intensity vecE, then the work done in deflecting it through an angle of 180° is

Question

An electric dipole of moment vecp is placed normal to the lines of force of electric intensity vecE, then the work done in deflecting it through an angle of 180° is (A) p E (B) +2 p E (C) -2 p E (D) zero

Tardigrade Admin · Accepted Answer

Work done =∫ limits90270 p E sin θ d θ =[-p E cos θ]90270=0 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/070cee81a5e3b7cdd076fa386a84926e-.png" />

Q. An electric dipole of moment $p$ is placed normal to the lines of force of electric intensity $E$ , then the work done in deflecting it through an angle of $18 0^{\circ}$ is

p E

+2 p E

-2 p E

zero

Work done $= 90 \int 270 pE sin θ d θ$
$= [- pE cos θ]_{90}^{270} = 0$

Q. An electric dipole of moment p​ is placed normal to the lines of force of electric intensity E, then the work done in deflecting it through an angle of 180∘ is

p E

+2 p E

-2 p E

zero

Work done =90∫270​pEsinθdθ =[−pEcosθ]90270​=0

Q. An electric dipole of moment $p$ is placed normal to the lines of force of electric intensity $E$ , then the work done in deflecting it through an angle of $18 0^{\circ}$ is

Work done $= 90 \int 270 pE sin θ d θ$
$= [- pE cos θ]_{90}^{270} = 0$