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  4. An electric dipole of moment vecp is placed normal to the lines of force of electric intensity vecE, then the work done in deflecting it through an angle of 180° is

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Q. An electric dipole of moment $\vec{p}$ is placed normal to the lines of force of electric intensity $\vec{E}$, then the work done in deflecting it through an angle of $180^{\circ}$ is

Electrostatic Potential and Capacitance

Solution:

Work done $=\int\limits_{90}^{270} p E \sin \theta d \theta$
$=[-p E \cos \theta]_{90}^{270}=0$
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