An electric dipole of moment vecp is lying along a uniform electric field vecE. The work done in rotating the dipole by 90° is :-

Question

An electric dipole of moment vecp is lying along a uniform electric field vecE. The work done in rotating the dipole by 90° is :- (A) p E (B)  √ 2 pE (C) pE/2 (D) 2pE

Tardigrade Admin · Accepted Answer

Work done in rotating a dipole from θ1 to θ2 is W = pE ( cos θ1- cos θ2) Here θ1=0° text and θ2=90° therefore W = pE

Q. An electric dipole of moment $p$ is lying along a uniform electric field $E$ . The work done in rotating the dipole by 90 $^{\circ}$ is :-

p E

$2$ pE

pE/2

2pE

Work done in rotating a dipole from $θ_{1}$ to $θ_{2}$ is
$W = pE (cos θ_{1} - cos θ_{2})$
Here $θ_{1} = 0^{\circ} and θ_{2} = 9 0^{\circ}$ therefore $W = pE$

Q. An electric dipole of moment p​ is lying along a uniform electric field E. The work done in rotating the dipole by 90∘ is :-

p E

2​ pE

pE/2

2pE

Work done in rotating a dipole from θ1​ to θ2​ is W=pE(cosθ1​−cosθ2​) Here θ1​=0∘ and θ2​=90∘ therefore W=pE

Q. An electric dipole of moment $p$ is lying along a uniform electric field $E$ . The work done in rotating the dipole by 90 $^{\circ}$ is :-

$2$ pE

Work done in rotating a dipole from $θ_{1}$ to $θ_{2}$ is
$W = pE (cos θ_{1} - cos θ_{2})$
Here $θ_{1} = 0^{\circ} and θ_{2} = 9 0^{\circ}$ therefore $W = pE$