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  4. An electric dipole of moment vecp is lying along a uniform electric field vecE. The work done in rotating the dipole by 90° is :-

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Q. An electric dipole of moment $\vec{p}$ is lying along a uniform electric field $\vec{E}$. The work done in rotating the dipole by 90$^{\circ}$ is :-

AIPMTAIPMT 2006Electrostatic Potential and Capacitance

Solution:

Work done in rotating a dipole from $\theta_{1} $ to $\theta_{2} $ is
$W = pE\, \left(\cos \theta_{1}-\cos \theta_{2}\right)$
Here $ \theta_{1}=0^{\circ} \text { and } \theta_{2}=90^{\circ} $ therefore $W = pE$