An electric dipole is placed making at an angle 60° with an electric field of strength 4 × 105 N / C. It experiences a torque equal to 8 √3 N - m. Calculate the charge on the dipole, if it is of length 4 cm.

Question

An electric dipole is placed making at an angle 60° with an electric field of strength 4 × 105 N / C. It experiences a torque equal to 8 √3 N - m. Calculate the charge on the dipole, if it is of length 4 cm. (A) 10-4 C (B) 10-3 C (C) 10-2 C (D) 10-6 C

Tardigrade Admin · Accepted Answer

τ= PE sin θ= q ( d ) E sin θ q =(τ/ dE sin θ)=(8 × √3/4 × 10-2 × 4 × 105 sin 60) =10-3 C

Q. An electric dipole is placed making at an angle $6 0^{\circ}$ with an electric field of strength $4 \times 1 0^{5} N / C$ . It experiences a torque equal to $83 N - m$ . Calculate the charge on the dipole, if it is of length $4 c m$ .

$1 0^{- 4} C$

$1 0^{- 3} C$

$1 0^{- 2} C$

$1 0^{- 6} C$

$τ = PE sin θ = q (d) E sin θ$
$q = \frac{τ}{d E s i n θ} = \frac{8 \times 3}{4 \times 1 0 ^{- 2} \times 4 \times 1 0 ^{5} s i n 60}$
$= 1 0^{- 3} C$

Q. An electric dipole is placed making at an angle 60∘ with an electric field of strength 4×105N/C. It experiences a torque equal to 83​N−m. Calculate the charge on the dipole, if it is of length 4cm.

10−4C

10−3C

10−2C

10−6C