An electric dipole is placed at an angle of 30° with an electric field intensity 2 × 105 N / C . It experiences a torque equal to 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is

Question

An electric dipole is placed at an angle of 30° with an electric field intensity 2 × 105 N / C . It experiences a torque equal to 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is (A) 8 mC (B) 4 mC (C) 6 mC (D) 2 mC

Tardigrade Admin · Accepted Answer

τ= pE sin θ τ= q ℓ operatornameEsin θ q =(τ/ℓ E sin θ) q =(4/2 × 10-2 × 2 × 105 × (1)2) q =2 × 10-3 C q =2 mC

Q. An electric dipole is placed at an angle of $3 0^{\circ}$ with an electric field intensity $2 \times 1 0^{5} N / C .$ It experiences a torque equal to $4 N m$ . The charge on the dipole, if the dipole length is $2 c m$ , is

$8 m C$

$4 m C$

$6 m C$

$2 m C$

$τ = pE sin θ$
$τ = q ℓ Esin θ$
$q = \frac{τ}{ℓ E s i n θ}$
$q = \frac{4}{2 \times 1 0 ^{- 2} \times 2 \times 1 0 ^{5} \times \frac{1}{2}}$
$q = 2 \times 1 0^{- 3} C$
$q = 2 m C$

Q. An electric dipole is placed at an angle of 30∘ with an electric field intensity 2×105N/C. It experiences a torque equal to 4Nm. The charge on the dipole, if the dipole length is 2cm, is

8mC

4mC

6mC

2mC