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Q. An electric dipole is placed at an angle of $30^{\circ}$ with an electric field intensity $2 \times 10^{5} N / C .$ It experiences a torque equal to $4\, Nm$. The charge on the dipole, if the dipole length is $2\, cm$, is

NEETNEET 2016Electric Charges and Fields

Solution:

$\tau= pE \sin \theta$
$\tau= q \ell \operatorname{Esin} \theta$
$q =\frac{\tau}{\ell E \sin \theta}$
$q =\frac{4}{2 \times 10^{-2} \times 2 \times 10^{5} \times \frac{1}{2}}$
$q =2 \times 10^{-3} C$
$q =2 mC$