An electric dipole is formed two particles fixed at the ends of a light rigid rad of length 1 The mass of each particle is m and chaises are -q and +q The system s suspended by a torsionless thread in ah electric field,of intensity E such that the dipole axis is parallel to the field if it is slightly displaced, the period of angular motion

Question

An electric dipole is formed two particles fixed at the ends of a light rigid rad of length 1 The mass of each particle is m and chaises are -q and +q The system s suspended by a torsionless thread in ah electric field,of intensity E such that the dipole axis is parallel to the field if it is slightly displaced, the period of angular motion (A) (1/2π)√(2qE/ml) (B) 2π √(ml/qE) (C) 2π √(ml/2qE) (D) (1/2π)√(ml/5qE)

Tardigrade Admin · Accepted Answer

Correct answer is (c) 2π √(ml/2qE)

$\frac{1}{2 π} \frac{2 qE}{m l}$

$2 π \frac{m l}{qE}$

$2 π \frac{m l}{2 qE}$

$\frac{1}{2 π} \frac{m l}{5 qE}$

Correct answer is (c) $2 π \frac{m l}{2 qE}$

2π1​ml2qE​​

2πqEml​​

2π2qEml​​

2π1​5qEml​​

Correct answer is (c) 2π2qEml​​

$\frac{1}{2 π} \frac{2 qE}{m l}$

$2 π \frac{m l}{qE}$

$2 π \frac{m l}{2 qE}$

$\frac{1}{2 π} \frac{m l}{5 qE}$

Correct answer is (c) $2 π \frac{m l}{2 qE}$