An electric current ‘I’ enters and leaves a uniform circular wire of radius r through dfiametrically opposite points. A particle carrying a charge q moves along the axis of the circular wire with speed v. What is the magnetic force experienced by the particle when it passes through the centre of the circle ?

Question

An electric current ‘I’ enters and leaves a uniform circular wire of radius r through dfiametrically opposite points. A particle carrying a charge q moves along the axis of the circular wire with speed v. What is the magnetic force experienced by the particle when it passes through the centre of the circle ? (A) qv(μ0i/a) (B) qv(μ0i/2a) (C) qv(μ0i/2π a) (D) Zero

Tardigrade Admin · Accepted Answer

Net magnetic fieldat centre = 0 vecF=q vecV× vecB=0

$q v \frac{μ _{0} i}{a}$

$q v \frac{μ _{0} i}{2 a}$

$q v \frac{μ _{0} i}{2 πa}$

Zero

$N e t ma g n e t i c f i e l d a t ce n t re = 0$
$F = q V \times B = 0$

qvaμ0​i​

qv2aμ0​i​

qv2πaμ0​i​

Zero

Netmagneticfieldatcentre=0 F=qV×B=0

$q v \frac{μ _{0} i}{a}$

$q v \frac{μ _{0} i}{2 a}$

$q v \frac{μ _{0} i}{2 πa}$

$N e t ma g n e t i c f i e l d a t ce n t re = 0$
$F = q V \times B = 0$