Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
An electric charge of 8.85× 10-13C is placed at the centre of a sphere of radius 1 m . The electric flux through the sphere is
Q. An electric charge of
8.85
×
1
0
−
13
C
is placed at the centre of a sphere of radius
1
m
. The electric flux through the sphere is
10078
240
J & K CET
J & K CET 2011
Electric Charges and Fields
Report Error
A
0.2
N
C
−
1
m
2
7%
B
0.1
N
C
−
1
m
2
66%
C
0.3
N
C
−
1
m
2
11%
D
0.01
N
C
−
1
m
2
16%
Solution:
Electric flux,
ϕ
=
E
.
A
ϕ
=
4
π
ε
0
1
×
r
2
q
⋅
4
π
r
2
=
4
π
ε
0
4
π
q
=
9
×
1
0
9
×
8.85
×
1
0
−
13
×
4
×
7
22
=
0.1
N
C
−
1
m
2