An athlete completes one round of a circular track of radius 10 m in 40 s. The distance covered by him in 2 min 20 s is

Question

An athlete completes one round of a circular track of radius 10 m in 40 s. The distance covered by him in 2 min 20 s is (A) 110 m (B) 70 m (C) 220 m (D) 140 m

Tardigrade Admin · Accepted Answer

Time period =40 s. No. of revolutions =( text Total time / text Time period ) =(140 s /40 s ) =3.5 Revolutions So, distance =3.5 × 2 π R =3.5 × 2 π × 10 =220 m

Q. An athlete completes one round of a circular track of radius $10 m$ in $40 s$ . The distance covered by him in $2 min 20 s$ is

110 m

70 m

220 m

140 m

Time period $= 40 s$ .
No. of revolutions $= \frac{Total time}{Time period}$
$= \frac{140 s}{40 s}$
$= 3.5$ Revolutions
So, distance $= 3.5 \times 2 π R$
$= 3.5 \times 2 π \times 10$
$= 220 m$

Q. An athlete completes one round of a circular track of radius 10m in 40s. The distance covered by him in 2min20s is