Thank you for reporting, we will resolve it shortly
Q.
An athlete completes one round of a circular track of radius $10\, m$ in $40\, s$. The distance covered by him in $2\, \min\, 20\,s$ is
ManipalManipal 2015
Solution:
Time period $=40\, s$.
No. of revolutions $=\frac{\text { Total time }}{\text { Time period }}$
$=\frac{140\, s }{40\, s }$
$=3.5$ Revolutions
So, distance $=3.5 \times 2 \pi R$
$=3.5 \times 2 \pi \times 10$
$=220\, m$