An arrow is shot into air. Its range is 200 m and its time of flight is 5 s. If g = 10 ms- 2 , then the horizontal component of velocity of the arrow is

Question

An arrow is shot into air. Its range is 200 m and its time of flight is 5 s. If g = 10 ms- 2 , then the horizontal component of velocity of the arrow is (A)  12.5 ms - 1  (B)  25 ms - 1  (C)  31.25 ms - 1  (D) 40 ms - 1

Tardigrade Admin · Accepted Answer

T = ( 2 u sin θ / g ) ..(i) Also horizontal range R = u cos θ × t R = ( u cos θ × 2 u sin θ / g ) (ii) Given T = S and R = 200 ∴ From Eqs. (i) and (ii), we get 5 = ( 2 u sin θ / g ) ..(iii) 200 = ( 2 u2 sin θ cos θ / g ) ..(iv) Dividing Eq. (iv) by Eq. (iii), we get ( 200 / 5) = u cos θ = 40 ms - 1

Q. An arrow is shot into air. Its range is $200 m$ and its time of flight is $5 s$ . If $g = 10 m s^{- 2}$ , then the horizontal component of velocity of the arrow is

$12.5 m s^{- 1}$

$25 m s^{- 1}$

$31.25 m s^{- 1}$

$40 m s^{- 1}$

Q. An arrow is shot into air. Its range is 200m and its time of flight is 5s. If g=10ms−2, then the horizontal component of velocity of the arrow is

12.5ms−1

25ms−1

31.25ms−1

40ms−1

T=g2usinθ​ ..(i) Also horizontal range R=ucosθ×t R=gucosθ×2usinθ​ (ii) Given T=S and R=200 ∴ From Eqs. (i) and (ii), we get 5=g2usinθ​ ..(iii) 200=g2u2sinθcosθ​ ..(iv) Dividing Eq. (iv) by Eq. (iii), we get 5200​=ucosθ=40ms−1

Q. An arrow is shot into air. Its range is $200 m$ and its time of flight is $5 s$ . If $g = 10 m s^{- 2}$ , then the horizontal component of velocity of the arrow is

$12.5 m s^{- 1}$

$25 m s^{- 1}$

$31.25 m s^{- 1}$

$40 m s^{- 1}$