An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is

Question

An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is (A) 0.02 (B) 1.1 (C) 20 (D) 196

Tardigrade Admin · Accepted Answer

( Δ P/p°) = ( 18 × 18/180 × 90) = 0.02

Q. An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is

0.02

1.1

20

196

$\frac{Δ P}{p ^{\circ}} = \frac{18 \times 18}{180 \times 90} = 0.02$

Q. An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is

0.02

1.1

20

196

p∘ΔP​=180×9018×18​=0.02

$\frac{Δ P}{p ^{\circ}} = \frac{18 \times 18}{180 \times 90} = 0.02$