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Tardigrade
Question
Chemistry
An aqueous solution freezes at -0.186° C (kf=1.86° ; kb=0.512°) What is the elevation in boiling point?
Q. An aqueous solution freezes at
−
0.18
6
∘
C
(
k
f
=
1.8
6
∘
;
k
b
=
0.51
2
∘
)
What is the elevation in boiling point?
3820
180
Chhattisgarh PMT
Chhattisgarh PMT 2005
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A
0.186
B
0.512
C
1.86
0.512
D
0.0512
Solution:
Δ
T
f
=
k
f
′
×
m
0.186
=
1.86
×
m
m
=
1.86
0.186
=
0.1
m
o
l
∴
Δ
T
b
=
k
b
×
molality
Δ
T
b
=
0.512
×
0.1
Δ
T
b
=
0.0512