Question

An amplitude modulated wave is as shown in figure. The value of peak carrier voltage and peak information voltage respectively are

• A. 25 V, 15 V
• B. 10 V, 15 V
• C. 15 V, 10 V
• D. 25 V, 5 V

Answer 1

Answer: (C)

From figure,
$V_{max}=\frac{50V}{2}=25V,V_{min}=\frac{10V}{2}=5V$
Peak carrier voltage,
$V_c=\frac{V_{max}+V_{min}}{2}=\frac{25V+5V}{2}=\frac{30V}{2}=15V$
Peak information voltage,
$V_m=\frac{V_{max}-V_{min}}{2}=\frac{25V-5V}{2}=\frac{20V}{2}=10V$