Question

An amplitude modulated wave is as shown in figure. The value of peak carrier voltage and peak information voltage respectively are

• A. 25 V, 15 V
• B. 10 V, 15 V
• C. 15 V, 10 V
• D. 25 V, 5 V

Answer 1

Answer: (C)

From figure,
$V_{max}=\frac{50\,V}{2}=25\,V, V_{min}=\frac{10\,V}{2}=5\,V$
Peak carrier voltage,
$V_{c}=\frac{V_{max}+V_{min}}{2}=\frac{25\,V+5\,V}{2}=\frac{30\,V}{2}=15\,V$
Peak information voltage,
$V_{m}=\frac{V_{max}-V_{min}}{2}=\frac{25\,V-5\,V}{2}=\frac{20\,V}{2}=10\,V$