An amide, C 3 H 7 NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamine reaction whereas C reduces Tollen's reagent. 'A' is:

Question

An amide, C 3 H 7 NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamine reaction whereas C reduces Tollen's reagent. 'A' is: (A) CH 3 CONHCH 3 (B) CH 3 CH 2 CONO 2 (C) HCONHC 2 H 5 (D)

Tardigrade Admin · Accepted Answer

As an acid (C) reduces Tollen’s reagent, (C) is a formic acid. B gives carbylamine reaction. So, B is a primary amine with two carbon atoms. B is ethyl amine. Therefore compound A has a structure <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6d442bb729ddd00e368c45e41144c822-.png" />

Q. An amide, $C_{3} H_{7} NO$ on hydrolysis gives an amine $(B)$ and an acid $(C) . B$ gives carbylamine reaction whereas $C$ reduces Tollen's reagent. $^{'} A^{'}$ is:

$C H_{3} CON H C H_{3}$

$C H_{3} C H_{2} CON O_{2}$

$H CON H C_{2} H_{5}$

As an acid $(C)$ reduces Tollen’s reagent, $(C)$ is a formic acid. B gives carbylamine reaction. So, $B$ is a primary amine with two carbon atoms. $B$ is ethyl amine. Therefore compound A has a structure

Q. An amide, C3​H7​NO on hydrolysis gives an amine (B) and an acid (C).B gives carbylamine reaction whereas C reduces Tollen's reagent. ′A′ is:

CH3​CONHCH3​

CH3​CH2​CONO2​

HCONHC2​H5​

As an acid (C) reduces Tollen’s reagent, (C) is a formic acid. B gives carbylamine reaction. So, B is a primary amine with two carbon atoms. B is ethyl amine. Therefore compound A has a structure

Q. An amide, $C_{3} H_{7} NO$ on hydrolysis gives an amine $(B)$ and an acid $(C) . B$ gives carbylamine reaction whereas $C$ reduces Tollen's reagent. $^{'} A^{'}$ is:

$C H_{3} CON H C H_{3}$

$C H_{3} C H_{2} CON O_{2}$

$H CON H C_{2} H_{5}$

As an acid $(C)$ reduces Tollen’s reagent, $(C)$ is a formic acid. B gives carbylamine reaction. So, $B$ is a primary amine with two carbon atoms. $B$ is ethyl amine. Therefore compound A has a structure