Question

An AM transmitter employs a $50\mu H$ coil and a $1nF$ capacitor. The carrier frequency will be

• A. 712 kHz
• B. 512 kHz
• C. 812 kHz
• D. 612 kHz

Answer 1

Answer: (A)

Here, $L=50\mu H=50\times 10^{-6}H$
and $C=1nF=10^{-9}F$
$f_C=\frac{1}{2\pi /\sqrt{LC}}=\frac{1}{2\times \frac{22}{7}\sqrt{50\times 10^{-6}\times 10^{-9}}}$
$=\frac{7\times 10^7}{44\sqrt{5}}Hz=711.5Hz\approx 712kHz$