An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μ F. The impedence of the circuit is

Question

An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μ F. The impedence of the circuit is (A) (π/5000) (B) (1000/π) (C) 500 π (D) (5000/π)

Tardigrade Admin · Accepted Answer

Impedence of a capacitor is X C =1 / ω C X C =(1/2 π fC )=(1/2 π × 50 × 2 × 10-6) =(5000/π)

Q. An alternating voltage of $220 V, 50 Hz$ frequency is applied across a capacitor of capacitance $2 μ F$ . The impedence of the circuit is

$\frac{π}{5000}$

$\frac{1000}{π}$

$500 π$

$\frac{5000}{π}$

Impedence of a capacitor is $X_{C} = 1/ ω C$
$X_{C} = \frac{1}{2 π f C} = \frac{1}{2 π \times 50 \times 2 \times 1 0 ^{- 6}}$
$= \frac{5000}{π}$

Q. An alternating voltage of 220V,50Hz frequency is applied across a capacitor of capacitance 2μF. The impedence of the circuit is

5000π​

π1000​

500π

π5000​