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  4. An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μ F. The impedence of the circuit is

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Q. An alternating voltage of $220\, V,\, 50\, Hz$ frequency is applied across a capacitor of capacitance $2 \mu F$. The impedence of the circuit is

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Solution:

Impedence of a capacitor is $X _{ C }=1 / \omega C$
$X _{ C }=\frac{1}{2 \pi fC }=\frac{1}{2 \pi \times 50 \times 2 \times 10^{-6}}$
$=\frac{5000}{\pi}$