Q.
An α -particle of mass 6.4×10−27kg and charge 3.2×10−19C is situated in a uniform electric field of 1.6×105Vm−1. The velocity of the particle at the end of 2×10−2m path when it starts from rest is
Force on a charge particle placed in a uniform electric field is given as, F=qE=mg ⇒E=qmg
From equation of motion, v2=u2+2as=(0)2+2as ⇒v=m2qE s=6.4×10−272×3.2×10−19×1.6×105×2×10−2 ⇒v=42×105m/s