An α-particle moving perpendicularly to a magnetic field of 0.2 wb/metre? experiences a force of 3.84 × 10-24 N. Then speed of α particle will be :

Question

An α-particle moving perpendicularly to a magnetic field of 0.2 wb/metre? experiences a force of 3.84 × 10-24 N. Then speed of α particle will be : (A)  6× 105 m/s  (B)  5× 10-5 m/s  (C)  1.2× 106 m/s  (D)  3.8 × 106 m/s

Tardigrade Admin · Accepted Answer

q α=2 e =2 × 1.6 × 10-19 F = qv β (3.89 × 1014)=(3.2 × 10-19) v (0.2) V =6 × 10+33 m / sec

Q. An $α$ -particle moving perpendicularly to a magnetic field of $0.2$ wb/metre? experiences a force of $3.84 \times 1 0^{- 24} N$ . Then speed of $α$ particle will be :

$6 \times 1 0^{5} m / s$

$5 \times 1 0^{- 5} m / s$

$1.2 \times 1 0^{6} m / s$

$3.8 \times 1 0^{6} m / s$

$q_{α} = 2 e = 2 \times 1.6 \times 1 0^{- 19}$
$F = q v β$
$(3.89 \times 1 0^{14}) = (3.2 \times 1 0^{- 19})_{v} (0.2)$
$V = 6 \times 1 0^{+ 33} m / sec$

Q. An α-particle moving perpendicularly to a magnetic field of 0.2 wb/metre? experiences a force of 3.84×10−24N. Then speed of α particle will be :

6×105m/s

5×10−5m/s

1.2×106m/s

3.8×106m/s