Question

An alpha particle is accelerated through a potential difference of $10^6$ volts. Its kinetic energy will be

• A. 1 MeV
• B. 2 MeV
• C. 4 MeV
• D. 8 MeV

Answer 1

Answer: (B)

$K=qV=2e\times 10^{6}J$
$=\frac{2e\times 10^6}{e}eV=2MeV$