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  4. An alpha particle is accelerated through a potential difference of 106 volts. Its kinetic energy will be

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Q. An alpha particle is accelerated through a potential difference of $10^{6}$ volts. Its kinetic energy will be

Electrostatic Potential and Capacitance

Solution:

$K=q V=2 e \times 10^{6} J$
$=\frac{2 e \times 10^{6}}{e} eV =2\, MeV$