Question

An $\alpha$ -particle in a cyclotron changes its velocity from $30km/s$ south to $40km/s$ west in $10$ second what is the magnitude of average acceleration during this time

• A. $5Km/s^2$
• B. $7Km/s^2$
• C. $9Km/s^2$
• D. $11Km/s^2$

Answer 1

Answer: (A)

$\begin{array}{lllllc}|\Delta v|& \text{ Magnitude }& \text{ of }& \text{ change }& \text{ in }& \text{ velocity }\end{array}$ $=\sqrt{(30{)}^2+(40{)}^2}=\sqrt{900+1600}$
$|\Delta v|=\sqrt{2500}=50km/s$
$|a|=\frac{50}{10}km/s^2$
$=5km/s^2$