Question

An $\alpha$ -particle in a cyclotron changes its velocity from $30\, km / s$ south to $40\, km / s$ west in $10$ second what is the magnitude of average acceleration during this time

• A. $5 Km / s ^{2}$
• B. $7 Km / s ^{2}$
• C. $9 Km / s ^{2}$
• D. $11 Km / s ^{2}$

Answer 1

Answer: (A)

$\begin{array}{lllll}|\Delta v | & \text { Magnitude } & \text { of } & \text { change } & \text { in } & \text { velocity }\end{array}$ $=\sqrt{(30)^{2}+(40)^{2}}=\sqrt{900+1600}$
$|\Delta v|=\sqrt{2500}=50\, km / s$
$| a |=\frac{50}{10} km / s ^{2} $
$=5\, km / s ^{2}$