An alkyl halide reacts with alcoholic ammonia in a sealed tube, the product formed will be

Question

An alkyl halide reacts with alcoholic ammonia in a sealed tube, the product formed will be (A) a primary amine (B) a secondary amine (C) a tertiary amine (D) a mixture of all the three

Tardigrade Admin · Accepted Answer

When an alkyl halide reacts with alcoholic ammonia in a sealed tube then a mixture of primary, secondary and tertiary amine is formed.

RX + N H_{3} \to pri-amine RN H_{2} + H X

RN H_{2} + XR \to sec- amine R_{2} N H + H X

R_{2} N H + XR \to ter-amine R_{3} N + H X

Q. An alkyl halide reacts with alcoholic ammonia in a sealed tube, the product formed will be

a primary amine

a secondary amine

a tertiary amine

a mixture of all the three

When an alkyl halide reacts with alcoholic ammonia in a sealed tube then a mixture of primary, secondary and tertiary amine is formed. RX+NH3​→ pri-amineRNH2​​+HX RNH2​+XR→ sec- amineR2​NH​+HX R2​NH+XR→ ter-amineR3​N​+HX

When an alkyl halide reacts with alcoholic ammonia in a sealed tube then a mixture of primary, secondary and tertiary amine is formed.

$RX + N H_{3} \to pri-amine RN H_{2} + H X$

$RN H_{2} + XR \to sec- amine R_{2} N H + H X$

$R_{2} N H + XR \to ter-amine R_{3} N + H X$