An alkyl cyanide forms an amide when it is treated with

Question

An alkyl cyanide forms an amide when it is treated with (A)  H2O + HCl  (B)  NaOH + H2O  (C)  H2O2 + NaOH  (D)  H2SO4 + H2O

Tardigrade Admin · Accepted Answer

Amides are produced by alkyl cyanides by shaking them with cold cone. HCl or by dissolving the nitriles in cone. H2SO4 and then pouring them into water. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/b94a4288e85a56299409efed35449386-.png" />

Q. An alkyl cyanide forms an amide when it is treated with

$H_{2} O + H Cl$

$N a O H + H_{2} O$

$H_{2} O_{2} + N a O H$

$H_{2} S O_{4} + H_{2} O$

Amides are produced by alkyl cyanides by shaking them with cold cone. $H Cl$ or by dissolving the nitriles in cone. $H_{2} S O_{4}$ and then pouring them into water.

Q. An alkyl cyanide forms an amide when it is treated with

H2​O+HCl

NaOH+H2​O

H2​O2​+NaOH

H2​SO4​+H2​O

Amides are produced by alkyl cyanides by shaking them with cold cone. HCl or by dissolving the nitriles in cone. H2​SO4​ and then pouring them into water.

$H_{2} O + H Cl$

$N a O H + H_{2} O$

$H_{2} O_{2} + N a O H$

$H_{2} S O_{4} + H_{2} O$

Amides are produced by alkyl cyanides by shaking them with cold cone. $H Cl$ or by dissolving the nitriles in cone. $H_{2} S O_{4}$ and then pouring them into water.