An alkyl bromide (X) reacts with Sodium in ether to form 4, 5 -diethyl octane, the compound X is

Question

An alkyl bromide (X) reacts with Sodium in ether to form 4, 5 -diethyl octane, the compound X is (A) CH3(CH2)3Br (B) CH3(CH2)5Br (C) CH3(CH2)3CH(Br)CH3 (D) CH3-(CH2)2 - CH(Br) - CH2 - CH3

Tardigrade Admin · Accepted Answer

Alkyl halides react with metallic Na in presence of dry ether to form symmetrical alkanes containing double the number of carbon atoms present in the alkyl halide. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/f3a4a155961b22bea7e7b09e794486e6-.png" /> This reaction is called Wurtz reaction

Q. An alkyl bromide $(X)$ reacts with Sodium in ether to form $4, 5$ -diethyl octane, the compound X is

$C H_{3} (C H_{2})_{3} B r$

$C H_{3} (C H_{2})_{5} B r$

$C H_{3} (C H_{2})_{3} C H (B r) C H_{3}$

$C H_{3} - (C H_{2})_{2} - C H (B r) - C H_{2} - C H_{3}$

Alkyl halides react with metallic $N a$ in presence of dry ether to form symmetrical alkanes containing double the number of carbon atoms present in the alkyl halide.

This reaction is called Wurtz reaction

Q. An alkyl bromide (X) reacts with Sodium in ether to form 4,5 -diethyl octane, the compound X is

CH3​(CH2​)3​Br

CH3​(CH2​)5​Br

CH3​(CH2​)3​CH(Br)CH3​

CH3​−(CH2​)2​−CH(Br)−CH2​−CH3​