Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
An alkene,C7H14 on reductive ozonolysis gave propanal and a ketone. The probable ketone is
Q. An alkene,
C
7
H
14
on reductive ozonolysis gave propanal and a ketone. The probable ketone is
3434
190
Aldehydes Ketones and Carboxylic Acids
Report Error
A
Acetone
14%
B
Ethyl methyl ketone
66%
C
2-Pentanone
13%
D
3-Pentanone
7%
Solution:
The aldehyde is
C
H
3
C
H
2
C
H
O
. The ketone can have four carbon atoms. It is therefore ethyl methyl ketone.