An alkane with molecular mass of 72 amu when brominated gives only one monobrominated product. The alkane is

Question

An alkane with molecular mass of 72 amu when brominated gives only one monobrominated product. The alkane is (A) pentane (B) 2-methylbutane (C) 2, 2-dimethylpropane (D) all the of the above

Tardigrade Admin · Accepted Answer

The alkane has the molecular formula, C5H12 . The isomers Solution

The isomers 3 has twelve equivalent 1° H's. It has no 2° or 3° hydrogens. Therefore, it gives only one monobrominated product.

Q. An alkane with molecular mass of 72 amu when brominated gives only one monobrominated product. The alkane is

pentane

2-methylbutane

2, 2-dimethylpropane

all the of the above

The alkane has the molecular formula, $C_{5} H_{12}$ . The isomers

The isomers 3 has twelve equivalent $1^{\circ}$ H's. It has no $2^{\circ}$ or $3^{\circ}$ hydrogens. Therefore, it gives only one monobrominated product.