An alkane C6H14(X) can be obtained by reduction of five different alkyl halides C6H13Cl (only structural isomers) with Zn—CH3COOH. The IUPAC name of X satisfying above condition is

Question

An alkane C6H14(X) can be obtained by reduction of five different alkyl halides C6H13Cl (only structural isomers) with Zn—CH3COOH. The IUPAC name of X satisfying above condition is (A) hexane (B) 2 -methyl pentane (C) 2, 3-dimethyl butane (D) 2, 2-dimethyl butane

Tardigrade Admin · Accepted Answer

2-methyl pentane has five types of hydrogen, therefore, it can be obtained by reduction of five different halides as: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/0c8270e5264574a7de9121af6cd5407b-.png" /> All of the above chloroalkanes on reduction with Zn/CH3COOH would give the same 2-methyl pentane

Q. An alkane $C_{6} H_{14} (X)$ can be obtained by reduction of five different alkyl halides $C_{6} H_{13} Cl$ (only structural isomers) with $Z n — C H_{3} COO H$ . The IUPAC name of $X$ satisfying above condition is

hexane

2 -methyl pentane

2, 3-dimethyl butane

2, 2-dimethyl butane

$2 -$ methyl pentane has five types of hydrogen, therefore, it can be obtained by reduction of five different halides as:

All of the above chloroalkanes on reduction with
$Z n / C H_{3} COO H$ would give the same $2 -$ methyl pentane

Q. An alkane C6​H14​(X) can be obtained by reduction of five different alkyl halides C6​H13​Cl (only structural isomers) with Zn—CH3​COOH. The IUPAC name of X satisfying above condition is