An airplane is flying vertically upwards. When it is at a height of 1000 m above the ground and moving at a speed of 367 m/s., a shot is fired at it with a speed of 567 m/s from a point directly below it. What should be the acceleration of airplane so that it may escape from being hit?

Question

An airplane is flying vertically upwards. When it is at a height of 1000 m above the ground and moving at a speed of 367 m/s., a shot is fired at it with a speed of 567 m/s from a point directly below it. What should be the acceleration of airplane so that it may escape from being hit? (A) > 5 m/s2 (B) > 10 m/s2 (C) < 10 m/s2 (D) Not possible

Tardigrade Admin · Accepted Answer

0=(200)2 -2(arel)(1000) or arel=20 m/s2

Q. An airplane is flying vertically upwards. When it is at a height of $1000 m$ above the ground and moving at a speed of $367 m / s$ ., a shot is fired at it with a speed of $567 m / s$ from a point directly below it. What should be the acceleration of airplane so that it may escape from being hit?

$> 5 m / s^{2}$

$> 10 m / s^{2}$

$< 10 m / s^{2}$

Not possible

$0 = (200)^{2} - 2 (a_{re l}) (1000)$

or $a_{re l} = 20 m / s^{2}$

Q. An airplane is flying vertically upwards. When it is at a height of 1000m above the ground and moving at a speed of 367m/s., a shot is fired at it with a speed of 567m/s from a point directly below it. What should be the acceleration of airplane so that it may escape from being hit?

>5m/s2

>10m/s2

<10m/s2

Not possible

0=(200)2−2(arel​)(1000) or arel​=20m/s2

$> 5 m / s^{2}$

$> 10 m / s^{2}$

$< 10 m / s^{2}$

$0 = (200)^{2} - 2 (a_{re l}) (1000)$

or $a_{re l} = 20 m / s^{2}$