An aircraft flying horizontally with the speed 480 kmh -1 releases a parachute at a height of 980 m from the ground. It will strike the ground at (use, g=10 ms -2 )

Question

An aircraft flying horizontally with the speed 480 kmh -1 releases a parachute at a height of 980 m from the ground. It will strike the ground at (use, g=10 ms -2 ) (A) 1 km (B) 2 km (C) 2.8 km (D) 1.867 km

Tardigrade Admin · Accepted Answer

Time taken by the parachute to fall through a height

h

of

980 m

t = \frac{2 h}{g} = \frac{2 \times 980}{10} = 14 s

Distance at which the parachute strikes the ground

=

Horizontal velocity

\times t

= 480 \times 14 \times \frac{1}{3600}

= \frac{6720}{3600} = 1.867 km

Q. An aircraft flying horizontally with the speed $480 km h^{- 1}$ releases a parachute at a height of $980 m$ from the ground. It will strike the ground at (use, $g = 10 m s^{- 2}$ )

$1 km$

$2 km$

$2.8 km$

$1.867 km$

Time taken by the parachute to fall through a height $h$ of $980 m$
$t = \frac{2 h}{g} = \frac{2 \times 980}{10} = 14 s$
Distance at which the parachute strikes the ground
$=$ Horizontal velocity $\times t$
$= 480 \times 14 \times \frac{1}{3600}$
$= \frac{6720}{3600} = 1.867 km$

Q. An aircraft flying horizontally with the speed 480kmh−1 releases a parachute at a height of 980m from the ground. It will strike the ground at (use, g=10ms−2 )

1km

2km

2.8km

1.867km