An aircraft executes a horizontal loop at a speed of 800 km / h with the wings banked at an angle of 30° . What is the radius of the loop?

Question

An aircraft executes a horizontal loop at a speed of 800 km / h with the wings banked at an angle of 30° . What is the radius of the loop? (A) 7.2 × 102 m (B) 9.615 m (C) 8.615 × 103 m (D) None

Tardigrade Admin · Accepted Answer

v =800 × (5/18)=222.2 m / s As we know that tan θ=(v2/r g) ⇒ r=(v2/g tan θ) r=(222.2 × 222.2/(1)√3 × 9.8) =(49372.84/9.8) × 1.71 r=5038 × 1.71=8615.05 =8.615 × 103 m

Q. An aircraft executes a horizontal loop at a speed of $800 km / h$ with the wings banked at an angle of $3 0^{\circ} .$ What is the radius of the loop?

$7.2 \times 1 0^{2} m$

$9.615 m$

$8.615 \times 1 0^{3} m$

None

$v = 800 \times \frac{5}{18} = 222.2 m / s$
As we know that
$tan θ = \frac{v ^{2}}{r g}$
$\Rightarrow r = \frac{v ^{2}}{g t a n θ}$
$r = \frac{222.2 \times 222.2}{\frac{1}{3} \times 9.8}$
$= \frac{49372.84}{9.8} \times 1.71$
$r = 5038 \times 1.71 = 8615.05$
$= 8.615 \times 1 0^{3} m$

Q. An aircraft executes a horizontal loop at a speed of 800km/h with the wings banked at an angle of 30∘. What is the radius of the loop?

7.2×102m

9.615m

8.615×103m