An air capacitor is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase

Question

An air capacitor is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase (A) the charge and the potential difference (B) the potential difference and the electric field (C) the electric field and the capacitance (D) the charge and the capacitance

Tardigrade Admin · Accepted Answer

C=(ε0 K A/d) ⇒ C propto K, Q =C V ⇒ Q propto C(∵ V= constant )

Q. An air capacitor is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase

the charge and the potential difference

the potential difference and the electric field

the electric field and the capacitance

the charge and the capacitance

$C = \frac{ε _{0} K A}{d} \Rightarrow C \propto K, Q$
$= C V \Rightarrow Q \propto C (∵ V =$ constant $)$

Q. An air capacitor is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase

the charge and the potential difference

the potential difference and the electric field

the electric field and the capacitance

the charge and the capacitance

C=dε0​KA​⇒C∝K,Q =CV⇒Q∝C(∵V= constant )

$C = \frac{ε _{0} K A}{d} \Rightarrow C \propto K, Q$
$= C V \Rightarrow Q \propto C (∵ V =$ constant $)$