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Physics
An air capacitor is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase
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Q. An air capacitor is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase
Electrostatic Potential and Capacitance
A
the charge and the potential difference
12%
B
the potential difference and the electric field
28%
C
the electric field and the capacitance
16%
D
the charge and the capacitance
44%
Solution:
$C=\frac{\varepsilon_{0} K A}{d} \Rightarrow C \propto K, Q$
$=C V \Rightarrow Q \propto C(\because V=$ constant $)$