Q.
An air bubble of radius 1mm is located at a depth of 20cm below water level. The excess pressure inside the bubble above the atmospheric pressure is [Given, the surface tension of water is 0.075Nm−1 and density is 1000kgm−3 ]
Let the atmospheric pressure be P0
Pressure just outside the bubble, P=P0+hρg
Pressure of air inside the bubble Pin=R+r2σ;σ is surface tension Pin=P0+hρg+r2σ ∴P′−P0=51×1000×9.8+1×10−32×0.075 =1960+150 =2110Pa