An aeroplane is moving with a horizontal velocity u at a height h. The velocity of packet dropped from it on the earths surface will be:

Question

An aeroplane is moving with a horizontal velocity u at a height h. The velocity of packet dropped from it on the earths surface will be: (A)  √u2-2 gh  (B)  2 gh  (C)  √2 gh  (D)  √u2+2 gh

Tardigrade Admin · Accepted Answer

Since, velocity is vector quantity, its horizontal component is u and vertical component is v and from equation of motion v=√2 gh Taking the resultant of u and v R=√u2+v2 =√u2+2 gh

Q. An aeroplane is moving with a horizontal velocity u at a height h. The velocity of packet dropped from it on the earths surface will be:

$u^{2} - 2 g h$

$2 g h$

$2 g h$

$u^{2} + 2 g h$

Since, velocity is vector quantity, its horizontal component is $u$ and vertical component is v and from equation of motion
$v = 2 g h$
Taking the resultant of $u$ and $v$
$R = u^{2} + v^{2}$
$= u^{2} + 2 g h$

Q. An aeroplane is moving with a horizontal velocity u at a height h. The velocity of packet dropped from it on the earths surface will be:

u2−2gh​

2gh

2gh​

u2+2gh​

Since, velocity is vector quantity, its horizontal component is u and vertical component is v and from equation of motion v=2gh​ Taking the resultant of u and v R=u2+v2​ =u2+2gh​

$u^{2} - 2 g h$

$2 g h$

$2 g h$

$u^{2} + 2 g h$

Since, velocity is vector quantity, its horizontal component is $u$ and vertical component is v and from equation of motion
$v = 2 g h$
Taking the resultant of $u$ and $v$
$R = u^{2} + v^{2}$
$= u^{2} + 2 g h$