An aeroplane in which the distance between the tips of the wings in 50 m is flying horizontally with a speed of 360 km h- 1 over a place where the vertical component of Earth's magnetic field is 2× 10- 4 Wb m- 2 . The potential difference between the tips of the wings would be

Question

An aeroplane in which the distance between the tips of the wings in 50 m is flying horizontally with a speed of 360 km h- 1 over a place where the vertical component of Earth's magnetic field is 2× 10- 4 Wb m- 2 . The potential difference between the tips of the wings would be (A) 0.1 V (B) 1.0 V (C) 0.2 V (D) 0.01 V

Tardigrade Admin · Accepted Answer

Here, l=50 m, v=360 km h- 1=100 m s- 1 B=2× 10- 4 Wb m- 2 Potential difference e=Blv=2× 10- 4× 50× 100=1 V

$0.1 V$

$1.0 V$

$0.2 V$

$0.01 V$

Here, $l = 50 m, v = 360 km h^{- 1} = 100 m s^{- 1}$
$B = 2 \times 1 0^{- 4} Wb m^{- 2}$
Potential difference $e = Bl v = 2 \times 1 0^{- 4} \times 50 \times 100 = 1 V$

Q. An aeroplane in which the distance between the tips of the wings in 50m is flying horizontally with a speed of 360kmh−1 over a place where the vertical component of Earth's magnetic field is 2×10−4 Wbm−2 . The potential difference between the tips of the wings would be

0.1V

1.0V

0.2V

0.01V

Here, l=50m,v=360kmh−1=100ms−1 B=2×10−4Wbm−2 Potential difference e=Blv=2×10−4×50×100=1V

$0.1 V$

$1.0 V$

$0.2 V$

$0.01 V$

Here, $l = 50 m, v = 360 km h^{- 1} = 100 m s^{- 1}$
$B = 2 \times 1 0^{- 4} Wb m^{- 2}$
Potential difference $e = Bl v = 2 \times 1 0^{- 4} \times 50 \times 100 = 1 V$