An aeroplane flying horizontally with a speed of 360 km h-1 releases a bomb at a height of 490 m from the ground. If g = 9.8 m s-2, it will strike the ground at

Question

An aeroplane flying horizontally with a speed of 360 km h-1 releases a bomb at a height of 490 m from the ground. If g = 9.8 m s-2, it will strike the ground at (A) 10 km (B) 100 km (C) 1 km (D) 16 km

Tardigrade Admin · Accepted Answer

Time taken by the bomb to fall through a height of

490 m

t = \frac{2 h}{g}

= \frac{2 \times 490}{9.8} = 10 s

Distance at which the bomb strikes the ground
= horizontal velocity

\times

time

= 360 km h^{- 1} \times 10 s

= 360 km h^{- 1} \times \frac{10}{3600} h

= 1 km

Q. An aeroplane flying horizontally with a speed of $360 km h^{- 1}$ releases a bomb at a height of $490 m$ from the ground. If $g = 9.8 m s^{- 2}$ , it will strike the ground at

$10 km$

$100 km$

$1 km$

$16 km$

Time taken by the bomb to fall through a height of $490 m$
$t = \frac{2 h}{g}$
$= \frac{2 \times 490}{9.8} = 10 s$
Distance at which the bomb strikes the ground
= horizontal velocity $\times$ time
$= 360 km h^{- 1} \times 10 s$
$= 360 km h^{- 1} \times \frac{10}{3600} h$
$= 1 km$

Q. An aeroplane flying horizontally with a speed of 360kmh−1 releases a bomb at a height of 490m from the ground. If g=9.8ms−2, it will strike the ground at

10km

100km

1km

16km