An acidic solution of Cu2+ containing 0.4 g of Cu2+ ions is electrolysed until all the copper is deposited. What is the volume of oxygen evolved at NTP ?

Question

An acidic solution of Cu2+ containing 0.4 g of Cu2+ ions is electrolysed until all the copper is deposited. What is the volume of oxygen evolved at NTP ? (A) 141 cc (B) 31.75 cc (C) 64 cc (D) 32 cc

Tardigrade Admin · Accepted Answer

Moles of Cu =(0.4/63.5)=6.3 × 10-3 mol Faraday used =2 × 6.3 × 10-3=12.6 × 10-3 mol Now for oxygen, beginarrayl 2 H 2 O longrightarrow O 2+4 H ++4 e - text Hence, 4 mol e - longrightarrow 22400 cm 3 text of O 2 . 12.6 × 10-3 longrightarrow (22400/2) × 12.6 × 10-3 cm 3 text of O 2 =141 cm 3 endarray

Q. An acidic solution of $C u^{2 +}$ containing $0.4 g$ of $C u^{2 +}$ ions is electrolysed until all the copper is deposited. What is the volume of oxygen evolved at $NTP$ ?

$141 cc$

$31.75 cc$

$64 cc$

$32 cc$

Q. An acidic solution of Cu2+ containing 0.4g of Cu2+ ions is electrolysed until all the copper is deposited. What is the volume of oxygen evolved at NTP ?

141cc

31.75cc

64cc

32cc

Moles of Cu=63.50.4​=6.3×10−3mol Faraday used =2×6.3×10−3=12.6×10−3mol Now for oxygen, <br/><br/>2H2​O⟶O2​+4H++4e−<br/>Hence, 4mole−⟶22400cm3 of O2​.<br/>12.6×10−3⟶222400​×12.6×10−3cm3 of O2​<br/>=141cm3<br/>​<br/>

Q. An acidic solution of $C u^{2 +}$ containing $0.4 g$ of $C u^{2 +}$ ions is electrolysed until all the copper is deposited. What is the volume of oxygen evolved at $NTP$ ?

$141 cc$

$31.75 cc$

$64 cc$

$32 cc$