Question

An AC circuit has $R=100\Omega ,C=2\mu F$ and $L=80mH,$ connected in series. The quality factor of the circuit is :

• A. 0.5
• B. 2
• C. 20
• D. 400

Answer 1

Answer: (B)

$Q=\frac{1}{R}\sqrt{\frac{L}{C}}=\frac{1}{100}\sqrt{\frac{80\times 10^{-3}}{2\times 10^{-6}}}$
$=\frac{1}{100}\sqrt{40\times 10^3}$
$=\frac{200}{100}=2$