An AC circuit consists of an inductor of inductance 0.5 H and a capacitor of capacitance 8 μ F in series. The current in the circuit is maximum when the angular frequency of AC source is

Question

An AC circuit consists of an inductor of inductance 0.5 H and a capacitor of capacitance 8 μ F in series. The current in the circuit is maximum when the angular frequency of AC source is (A) 500 rad/sec (B) 2 × 105 rad / sec (C) 4000 rad/sec (D) 5000 rad/sec

Tardigrade Admin · Accepted Answer

Current will be maximum at the condition of resonance. So resonant frequency, ω0=(1/√L C) =(1/√0.5 × 8 × 10-6) =500 rad/s

Q. An AC circuit consists of an inductor of inductance $0.5 H$ and a capacitor of capacitance $8 μ F$ in series. The current in the circuit is maximum when the angular frequency of AC source is

$500 r a d / sec$

$2 \times 1 0^{5} r a d / sec$

$4000 r a d / sec$

$5000 r a d / sec$

Current will be maximum at the condition of resonance.
So resonant frequency, $ω_{0} = \frac{1}{L C}$
$= \frac{1}{0.5 \times 8 \times 1 0 ^{- 6}}$
$= 500$ rad/s

Q. An AC circuit consists of an inductor of inductance 0.5H and a capacitor of capacitance 8μF in series. The current in the circuit is maximum when the angular frequency of AC source is

500rad/sec

2×105rad/sec

4000rad/sec

5000rad/sec