Among the following, the one that has dimension of the coefficient of friction is

Question

Among the following, the one that has dimension of the coefficient of friction is (A) [M2 L2 T] (B) [M0 L0 T0] (C) [M L3 T- 2] (D) [M2 L2 T- 2]

Tardigrade Admin · Accepted Answer

Limiting friction is given as fl=μ sN So dimensions of Coefficient of friction is [μ s]=[(fl/N)]=M0L0T0 So Coefficient of friction is unitless and dimensionless.

Q. Among the following, the one that has dimension of the coefficient of friction is

$[M^{2} L^{2} T]$

$[M^{0} L^{0} T^{0}]$

$[M L^{3} T^{- 2}]$

$[M^{2} L^{2} T^{- 2}]$

Limiting friction is given as $f_{l} = μ_{s} N$
So dimensions of Coefficient of friction is
$[μ_{s}] = [\frac{f _{l}}{N}] = M^{0} L^{0} T^{0}$
So Coefficient of friction is unitless and dimensionless.

Q. Among the following, the one that has dimension of the coefficient of friction is

[M2L2T]

[M0L0T0]

[ML3T−2]

[M2L2T−2]

Limiting friction is given as fl​=μs​N So dimensions of Coefficient of friction is [μs​]=[Nfl​​]=M0L0T0 So Coefficient of friction is unitless and dimensionless.

$[M^{2} L^{2} T]$

$[M^{0} L^{0} T^{0}]$

$[M L^{3} T^{- 2}]$

$[M^{2} L^{2} T^{- 2}]$

Limiting friction is given as $f_{l} = μ_{s} N$
So dimensions of Coefficient of friction is
$[μ_{s}] = [\frac{f _{l}}{N}] = M^{0} L^{0} T^{0}$
So Coefficient of friction is unitless and dimensionless.